Next, turn nonagon on 5.5 * clockwise. In this position we again see that azimuths of Uluru and Por Bajin are perpendicular to each other and the direction to Tiwanaku differs from azimuth of Uluru on 30 *. Now, thanks to nonagon, we see that azimuths of Angkor and Sigiriya are symmetric relatively to the direction to Uluru and are separated from it on 20 * with small errors.
As we remember, MD is removed on the same distance from GP and Por Bajin. Distance to Uluru is exactly 80 * in angular terms. This means that MD and Uluru are situated relatively to each other according to nonagon. With Sigiriya MD is located according to octagon, the angular distance between them is close to half of 45 * between them are 22.8* along the arc of globe.
The angular distance between MD and Angkor is 36.1 *. This means that Angkor and MD divide the circle connecting them according to pentagram. See article "PENTAGRAM IN THE ARRANGEMENT OF KEY POINTS OF SDMS."
Distance from MD to Tiwanaku is 15418 km or 138.7 * in the angular terms. It is 6 time more than the distance from MD to Sigiriya, which constitutes  2523 km or 22.8 *. 15418/2523 = 6.1.
Come on farther. In the point of Tiwanaku azimuths of MD and Angkor are located according to octagon, oriented to the cardinal points. Between them are 45 *, with the error of + 0.14 *.
In the point of Sigiriya between azimuths of Angkor and Por Bajin are 60 *. Between azimuths of MD and Por Bajin are 45 *.
In the point of Angkor, azimuths of Tiwanaku and Por Bajin are located according to pentagram, between them are 108 *, with the error of 0.46 *. But the most amazing thing is that between azimuths of MD and Sigiriya in Angkor are 40 *. Between azimuths of Tiwanaku and Uluru are 100 *.
Let us pass to Por Bajin. In this point the angle between azimuths of MD and Sigiriya is close to 30 *, and between azimuths of Uluru and Angkor are 20 *.
